What is the domain of f(x)=sqrt(x^2-2x) ?

The domain of f(x)=sqrt(x^2-2x) is x = 2

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domain of f(x)=sqrt(x^2-2x)

domain

f (x) = x^{2} - 2 x

x \leq 0 or x \geq 2

Interval Notation

(- \infty, 0] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 2

The function domain

x \leq 0 or x \geq 2

f (x) = x - 17

\frac{7}{x ^{2} + 7 x - 8}

y = 2 x + 3, (4, 7)

- 5 x + 2 y = 7

f (x) = x^{5} - 5 x^{4}

What is the domain of f(x)=sqrt(x^2-2x) ?
The domain of f(x)=sqrt(x^2-2x) is x<= 0\lor x>= 2