What is the domain of f(x)=sqrt(x-17) ?

The domain of f(x)=sqrt(x-17) is x>= 17

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domain of f(x)=sqrt(x-17)

domain

f (x) = x - 17

x \geq 17

Interval Notation

[17, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 17

The function domain

x \geq 17

\frac{7}{x ^{2} + 7 x - 8}

y = 2 x + 3, (4, 7)

- 5 x + 2 y = 7

f (x) = x^{5} - 5 x^{4}

f (x) = \frac{x ^{2} - x + 6}{x + 3}