What is the domain of (x+2)/(sqrt(x-8)) ?

The domain of (x+2)/(sqrt(x-8)) is x>8

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domain of (x+2)/(sqrt(x-8))

domain

\frac{x + 2}{x - 8}

x > 8

Interval Notation

(8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 8

Find undefined (singularity) points:

x = 8

Combine real regions and undefined points for final function domain

x > 8

f (x) = - 2 x + 2

y = 3 x - 6

f (x) = - 2 x + 5 y = 20

f (x) = x^{4} + x^{3} - 4 x^{2} + 5

f (x) = \frac{4 x ^{2}}{x ^{2} - 9}

What is the domain of (x+2)/(sqrt(x-8)) ?
The domain of (x+2)/(sqrt(x-8)) is x>8