What is the domain of (sqrt(x))/(x^2-1) ?

The domain of (sqrt(x))/(x^2-1) is 0 1

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domain of (sqrt(x))/(x^2-1)

domain

\frac{x}{x ^{2} - 1}

0 \leq x < 1 or x > 1

Interval Notation

[0, 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

0 \leq x < 1 or x > 1

f (x) = \frac{x ^{2} - 1}{4 x - 4}

f (x) = \frac{1}{4} x^{2} + 2 x + 6

f (x) = ln (9 - t^{2})

y = \frac{- 7}{1 x - 3}

f (x) = \frac{60}{x ( x + 4 )}

What is the domain of (sqrt(x))/(x^2-1) ?
The domain of (sqrt(x))/(x^2-1) is 0<= x<1\lor x>1