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Popular >

extreme f(x)= 1/4 x^2+2x+6

Solution

extreme points

f (x) = \frac{1}{4} x^{2} + 2 x + 6

Solution

Minimum (- 4, 2)

Solution steps

f^{'} (x) = \frac{x}{2} + 2

Find intervals:

Decreasing

: - \infty < x < - 4,

Increasing

: - 4 < x < \infty

Plug

x = - 4

into

\frac{1}{4} x^{2} + 2 x + 6 : 2

Minimum (- 4, 2)

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f (x) = ln (9 - t^{2})

range of y=(-7)/(1x-3)range

y = \frac{- 7}{1 x - 3}

range of f(x)=(60)/(x(x+4))range

f (x) = \frac{60}{x ( x + 4 )}

parity (5^x)/(5^x+3^x)parity

\frac{5 ^{x}}{5 ^{x} + 3 ^{x}}

inverse of f(x)= 4/(x+3)+2 inverse

f (x) = \frac{4}{x + 3} + 2

Frequently Asked Questions (FAQ)

What is the extreme f(x)= 1/4 x^2+2x+6 ?
The extreme f(x)= 1/4 x^2+2x+6 is Minimum(-4,2)