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midpoint
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domain of f(x)=sqrt(-x-2)periodicity of-cos(2(θ-pi/4))domain of f(x)=(x+6)/(x^2-1)critical f(x)=x^3-12xdomain of f(x)=((x-1))/((x^2-1))
Frequently Asked Questions (FAQ)
What is the midpoint (2,-4),(4,8) ?
The midpoint (2,-4),(4,8) is (3,2)