What is the domain of f(x)=((x-1))/((x^2-1)) ?

The domain of f(x)=((x-1))/((x^2-1)) is x 1

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domain of f(x)=((x-1))/((x^2-1))

domain

f (x) = \frac{( x - 1 )}{( x ^{2} - 1 )}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

\frac{2}{x + 2} + 3

p (w) = \frac{2}{3} w - 8

y = - 2 x - 1

e^{- x^{2}}

f (x) = \frac{6 ^{x}}{2}

What is the domain of f(x)=((x-1))/((x^2-1)) ?
The domain of f(x)=((x-1))/((x^2-1)) is x<-1\lor-1<x<1\lor x>1