What is the domain of (x-6)/(x^2-x-12) ?

The domain of (x-6)/(x^2-x-12) is x 4

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domain of (x-6)/(x^2-x-12)

domain

\frac{x - 6}{x ^{2} - x - 12}

x < - 3 or - 3 < x < 4 or x > 4

Interval Notation

(- \infty, - 3) \cup (- 3, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - 3

The function domain

x < - 3 or - 3 < x < 4 or x > 4

f (x) = \frac{- 6 x + 8}{8 x - 3}

\frac{x - 1}{x + 7}

(3, 3), (- 5, 5)

f (x) = \frac{1}{6 ( 2 x + 4 ) - 12}

f (x) = \frac{2 x ^{3}}{x ^{5}}

What is the domain of (x-6)/(x^2-x-12) ?
The domain of (x-6)/(x^2-x-12) is x<-3\lor-3<x<4\lor x>4