What is the domain of f(x)= 1/(6(sqrt(2x+4))-12) ?

The domain of f(x)= 1/(6(sqrt(2x+4))-12) is -2 0

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domain of f(x)= 1/(6(sqrt(2x+4))-12)

domain

f (x) = \frac{1}{6 ( 2 x + 4 ) - 12}

- 2 \leq x < 0 or x > 0

Interval Notation

[- 2, 0) \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 2 \leq x < 0 or x > 0

f (x) = \frac{2 x ^{3}}{x ^{5}}

2 x - 10

2 x + 4 y = - 1

f (x) = 2 - x - 1

\frac{1}{x}

What is the domain of f(x)= 1/(6(sqrt(2x+4))-12) ?
The domain of f(x)= 1/(6(sqrt(2x+4))-12) is -2<= x<0\lor x>0