What is the domain of sqrt(x^2+2x+2\sqrt{x^2+2x)} ?

The domain of sqrt(x^2+2x+2\sqrt{x^2+2x)} is x = 0

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domain of sqrt(x^2+2x+2\sqrt{x^2+2x)}

domain

x^{2} + 2 x + 2 x^{2} + 2 x

x \leq - 2 or x \geq 0

Interval Notation

(- \infty, - 2] \cup [0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 0

The function domain

x \leq - 2 or x \geq 0

y = \frac{ln ( x ^{2} - 4 )}{2 x ^{2} + x - 15}

f (x) = 13 x - 9

y = 5 x - 5

f (x) = sin (π + 6 x)

\frac{x - 6}{x ^{2} - x - 12}

What is the domain of sqrt(x^2+2x+2\sqrt{x^2+2x)} ?
The domain of sqrt(x^2+2x+2\sqrt{x^2+2x)} is x<=-2\lor x>= 0