What is the extreme f(x)=x^3-12x^2-27x+9 ?

The extreme f(x)=x^3-12x^2-27x+9 is Maximum(-1,23),Minimum(9,-477)

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extreme f(x)=x^3-12x^2-27x+9

extreme points

f (x) = x^{3} - 12 x^{2} - 27 x + 9

Maximum (- 1, 23), Minimum (9, - 477)

Solution steps

f^{'} (x) = 3 x^{2} - 24 x - 27

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 9,

Increasing

: 9 < x < \infty

Plug

x = - 1

into

x^{3} - 12 x^{2} - 27 x + 9 : 23

Maximum (- 1, 23)

Plug

x = 9

into

x^{3} - 12 x^{2} - 27 x + 9 : - 477

Minimum (9, - 477)

Maximum (- 1, 23), Minimum (9, - 477)

f (x) = - x^{4} - 4 x^{3} + 8 x - 1

f (x) = 2 x^{3} - 3 x^{2} + 5 x - 5

f (x) = \frac{x - 9}{4}

f (x) = 5 sin (x)

f (x) = x^{2} + 3 x - 4

What is the extreme f(x)=x^3-12x^2-27x+9 ?
The extreme f(x)=x^3-12x^2-27x+9 is Maximum(-1,23),Minimum(9,-477)