What is the inflection f(x)=2x^3-3x^2+5x-5 ?

The inflection f(x)=2x^3-3x^2+5x-5 is (1/2 ,-3)

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inflection f(x)=2x^3-3x^2+5x-5

inflection points

f (x) = 2 x^{3} - 3 x^{2} + 5 x - 5

(\frac{1}{2}, - 3)

Solution steps

f^{''} (x) = 12 x - 6

Find intervals:

Concave Downward

: - \infty < x < \frac{1}{2},

Concave Upward

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

2 x^{3} - 3 x^{2} + 5 x - 5 : - 3

(\frac{1}{2}, - 3)

f (x) = \frac{x - 9}{4}

f (x) = 5 sin (x)

f (x) = x^{2} + 3 x - 4

f (x) = 2 x^{3} - 1

What is the inflection f(x)=2x^3-3x^2+5x-5 ?
The inflection f(x)=2x^3-3x^2+5x-5 is (1/2 ,-3)