What is the critical f(x)=8t^{2/3}+t^{5/3} ?

The critical f(x)=8t^{2/3}+t^{5/3} is t=-16/5 ,t=0

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critical f(x)=8t^{2/3}+t^{5/3}

critical points

f (x) = 8 t^{\frac{2}{3}} + t^{\frac{5}{3}}

t = - \frac{16}{5}, t = 0

Solution steps

8 t^{\frac{2}{3}} + t^{\frac{5}{3}}

Find where

f^{'} (t)

is equal to zero or undefined

t = - \frac{16}{5}, t = 0

Identify critical points not in

f (t)

domain

Domain of

8 t^{\frac{2}{3}} + t^{\frac{5}{3}} : - \infty < t < \infty

All critical points are in domain

t = - \frac{16}{5}, t = 0

f (x) = 1 - 4 x^{2}

5 (\frac{1}{4})^{x}

(- 2, - 5), (- 4, - 2)

f (x) = x^{4}

1 - 1 - x^{2}

What is the critical f(x)=8t^{2/3}+t^{5/3} ?
The critical f(x)=8t^{2/3}+t^{5/3} is t=-16/5 ,t=0