What is the inverse of f(x)=sqrt(1-4x^2) ?

The inverse of f(x)=sqrt(1-4x^2) is sqrt(-(x^2-1)/4),-sqrt(-(x^2-1)/4)

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inverse of f(x)=sqrt(1-4x^2)

inverse

f (x) = 1 - 4 x^{2}

- \frac{x ^{2} - 1}{4}, - - \frac{x ^{2} - 1}{4}

Solution steps

y = 1 - 4 x^{2}

Replace

x

with

y

x = 1 - 4 y^{2}

Solve for

y, x = 1 - 4 y^{2}

- \frac{x ^{2} - 1}{4}, - - \frac{x ^{2} - 1}{4}

5 (\frac{1}{4})^{x}

(- 2, - 5), (- 4, - 2)

f (x) = x^{4}

1 - 1 - x^{2}

m = 7, (0, 6)

What is the inverse of f(x)=sqrt(1-4x^2) ?
The inverse of f(x)=sqrt(1-4x^2) is sqrt(-(x^2-1)/4),-sqrt(-(x^2-1)/4)