What is the domain of f(x)= 3/(4x^2-1) ?

The domain of f(x)= 3/(4x^2-1) is x 1/2

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domain of f(x)= 3/(4x^2-1)

domain

f (x) = \frac{3}{4 x ^{2} - 1}

x < - \frac{1}{2} or - \frac{1}{2} < x < \frac{1}{2} or x > \frac{1}{2}

Solution steps

Find undefined (singularity) points:

x = \frac{1}{2}, x = - \frac{1}{2}

The function domain

x < - \frac{1}{2} or - \frac{1}{2} < x < \frac{1}{2} or x > \frac{1}{2}

\frac{x - 7}{x ^{2} - 49}

\frac{4 x + 7}{8 - 5 x}

(1 \frac{2}{5}, \frac{6}{5}), (\frac{7}{4}, \frac{1}{4})

(3, - 4), (5, 1)

f (x) = - cos (\frac{6 x}{7})

What is the domain of f(x)= 3/(4x^2-1) ?
The domain of f(x)= 3/(4x^2-1) is x<-1/2 \lor-1/2 <x< 1/2 \lor x> 1/2