What is the midpoint (1 2/5 , 6/5),(7/4 , 1/4) ?

The midpoint (1 2/5 , 6/5),(7/4 , 1/4) is (43/40 , 29/40)

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midpoint (1 2/5 , 6/5),(7/4 , 1/4)

midpoint

(1 \frac{2}{5}, \frac{6}{5}), (\frac{7}{4}, \frac{1}{4})

(\frac{43}{40}, \frac{29}{40})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (1 \frac{2}{5}, \frac{6}{5}), (x_{2}, y_{2}) = (\frac{7}{4}, \frac{1}{4})

= (\frac{\frac{7}{4} + 1 \cdot \frac{2}{5}}{2}, \frac{\frac{1}{4} + \frac{6}{5}}{2})

Refine

= (\frac{43}{40}, \frac{29}{40})

(3, - 4), (5, 1)

f (x) = - cos (\frac{6 x}{7})

y = \frac{3 x}{x ^{2} - 36}

\frac{x - 1}{x ^{2} - 1}

What is the midpoint (1 2/5 , 6/5),(7/4 , 1/4) ?
The midpoint (1 2/5 , 6/5),(7/4 , 1/4) is (43/40 , 29/40)