What is the inflection f(x)=2x^3-3x^2+7x-9 ?

The inflection f(x)=2x^3-3x^2+7x-9 is (1/2 ,-6)

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inflection f(x)=2x^3-3x^2+7x-9

inflection points

f (x) = 2 x^{3} - 3 x^{2} + 7 x - 9

(\frac{1}{2}, - 6)

Solution steps

f^{''} (x) = 12 x - 6

Find intervals:

Concave Downward

: - \infty < x < \frac{1}{2},

Concave Upward

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

2 x^{3} - 3 x^{2} + 7 x - 9 : - 6

(\frac{1}{2}, - 6)

f (x) = \frac{5}{8 + x}

f (x) = x - 2

\frac{1}{6} x - 5

f (x) = \frac{3}{4 x ^{2} - 1}

\frac{x - 7}{x ^{2} - 49}

What is the inflection f(x)=2x^3-3x^2+7x-9 ?
The inflection f(x)=2x^3-3x^2+7x-9 is (1/2 ,-6)