What is the critical x^4-x^2 ?

The critical x^4-x^2 is x=-1/(sqrt(2)),x=0,x= 1/(sqrt(2))

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critical x^4-x^2

critical points

x^{4} - x^{2}

x = - \frac{1}{2}, x = 0, x = \frac{1}{2}

Solution steps

x^{4} - x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{2}, x = 0, x = \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

x^{4} - x^{2} : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{2}, x = 0, x = \frac{1}{2}

f (x) = \frac{7}{x - 4}

y = 11 x - 5

(x^{2} - 9)^{6}

4 - x^{2}

f (x) = \frac{x + 1}{x - 1}

What is the critical x^4-x^2 ?
The critical x^4-x^2 is x=-1/(sqrt(2)),x=0,x= 1/(sqrt(2))