What is the critical sqrt(4-x^2) ?

The critical sqrt(4-x^2) is x=-2,x=0,x=2

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critical sqrt(4-x^2)

critical points

4 - x^{2}

x = - 2, x = 0, x = 2

Solution steps

4 - x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

4 - x^{2} : - 2 \leq x \leq 2

All critical points are in domain

x = - 2, x = 0, x = 2

f (x) = \frac{x + 1}{x - 1}

(- 1, 5), (- 5, 5)

f (x) = \frac{5}{2 x ^{2} + 1}

(5, - 4), (- 1, - 4)

\frac{x ^{3}}{x + 2}