What is the domain of f(x)= x/(sqrt(25-x^2)) ?

The domain of f(x)= x/(sqrt(25-x^2)) is -5<x<5

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domain of f(x)= x/(sqrt(25-x^2))

domain

f (x) = \frac{x}{25 - x ^{2}}

- 5 < x < 5

Solution steps

Find non-negative values for radicals:

- 5 \leq x \leq 5

Find undefined (singularity) points:

x = 5, x = - 5

Combine real regions and undefined points for final function domain

- 5 < x < 5

f (x) = x^{2}

f (x) = x^{2} - 4

f (x) = \frac{1}{x ^{2} - x - 6}

f (x) = x e^{- 4 π x}

f (x) = \frac{3 x}{2 x + 1}

What is the domain of f(x)= x/(sqrt(25-x^2)) ?
The domain of f(x)= x/(sqrt(25-x^2)) is -5<x<5