What is the domain of f(x)= 1/(x^2-x-6) ?

The domain of f(x)= 1/(x^2-x-6) is x 3

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domain of f(x)= 1/(x^2-x-6)

domain

f (x) = \frac{1}{x ^{2} - x - 6}

x < - 2 or - 2 < x < 3 or x > 3

Solution steps

Find undefined (singularity) points:

x = 3, x = - 2

The function domain

x < - 2 or - 2 < x < 3 or x > 3

f (x) = x e^{- 4 π x}

f (x) = \frac{3 x}{2 x + 1}

f (x) = \frac{( x + 19 )}{x - 17}

f (x) = \frac{2}{( x - 1 ) ^{3}}

f (x) = - 2 x^{2} + 12 x - 20

What is the domain of f(x)= 1/(x^2-x-6) ?
The domain of f(x)= 1/(x^2-x-6) is x<-2\lor-2<x<3\lor x>3