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Popular >

midpoint (-4,1),(2,-3)

Solution

midpoint

(- 4, 1), (2, - 3)

Solution

(- 1, - 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 4, 1), (x_{2}, y_{2}) = (2, - 3)

= (\frac{2 - 4}{2}, \frac{- 3 + 1}{2})

Refine

= (- 1, - 1)

Popular Examples

domain of 1/x+3 domain

\frac{1}{x} + 3

f (x) = x^{2} - 2 x - 3

domain of y=-1 domain

y = - 1

extreme f(x)= 1/3 x^3-x^2+x+5 extreme points

f (x) = \frac{1}{3} x^{3} - x^{2} + x + 5

perpendicular y= 1/5 x-3,(-2,5)perpendicular

y = \frac{1}{5} x - 3, (- 2, 5)

Frequently Asked Questions (FAQ)

What is the midpoint (-4,1),(2,-3) ?
The midpoint (-4,1),(2,-3) is (-1,-1)