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midpoint
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domain of 1/x+3f(x)=x^2-2x-3extreme f(x)= 1/3 x^3-x^2+x+5perpendicular y= 1/5 x-3,(-2,5)inverse of f(x)=(x-5)^{1/5}
Frequently Asked Questions (FAQ)
What is the midpoint (-4,1),(2,-3) ?
The midpoint (-4,1),(2,-3) is (-1,-1)