What is the perpendicular y= 1/5 x-3,(-2,5) ?

The perpendicular y= 1/5 x-3,(-2,5) is y=-5x-5

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perpendicular y= 1/5 x-3,(-2,5)

perpendicular

y = \frac{1}{5} x - 3, (- 2, 5)

y = - 5 x - 5

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{1}{5} x - 3

that passes through

(- 2, 5)

Find the slope of

y = \frac{1}{5} x - 3 : m = \frac{1}{5}

Compute the slope of the perpendicular line:

m_{p} = - 5

Find the line with slope m=

- 5

and passing through

(- 2, 5) : y = - 5 x - 5

y = - 5 x - 5

f (x) = (x - 5)^{\frac{1}{5}}

f (x) = x^{\frac{5}{3}} - 5 x^{\frac{2}{3}}

f (x) = \frac{4 e ^{x}}{e ^{x}}

f (x) = \frac{2 x + 3}{x + 2}

f (x) = \frac{6}{x + 4} \cdot \frac{1}{2 - x}

What is the perpendicular y= 1/5 x-3,(-2,5) ?
The perpendicular y= 1/5 x-3,(-2,5) is y=-5x-5