What is the inverse of f(x)=(3-4x)/(8x-1) ?

The inverse of f(x)=(3-4x)/(8x-1) is (3+x)/(4(1+2x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(3-4x)/(8x-1)

inverse

f (x) = \frac{3 - 4 x}{8 x - 1}

\frac{3 + x}{4 ( 1 + 2 x )}

Solution steps

y = \frac{3 - 4 x}{8 x - 1}

Replace

x

with

y

x = \frac{3 - 4 y}{8 y - 1}

Solve for

y, x = \frac{3 - 4 y}{8 y - 1}

\frac{3 + x}{4 ( 1 + 2 x )}

\frac{x ^{3} + 3 x ^{2} - 4 x}{- 4 x ^{2} + 4 x + 8}

f (x) = \frac{2 ( x ^{2} - 9 )}{x ^{2} - 4}

f (x) = 6 - x - x^{2}

(x + 6) (x - 1)^{2}

f (x) = - \frac{3}{∣ x + 2 ∣}

What is the inverse of f(x)=(3-4x)/(8x-1) ?
The inverse of f(x)=(3-4x)/(8x-1) is (3+x)/(4(1+2x))