What is the critical (x+6)(x-1)^2 ?

The critical (x+6)(x-1)^2 is x=-11/3 ,x=1

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critical (x+6)(x-1)^2

critical points

(x + 6) (x - 1)^{2}

x = - \frac{11}{3}, x = 1

Solution steps

(x + 6) (x - 1)^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{11}{3}, x = 1

Identify critical points not in

f (x)

domain

Domain of

(x + 6) (x - 1)^{2} : - \infty < x < \infty

All critical points are in domain

x = - \frac{11}{3}, x = 1

f (x) = - \frac{3}{∣ x + 2 ∣}

f (x) = - \frac{1}{x ^{4}} - 3

\frac{5 x - 3}{2 x + 1}

f (x) = \frac{3 x - 6}{- x ^{2} - 2 x + 8}

f (x) = \frac{x ^{2} + 2 x - 24}{x ^{2} - 16}