What is the inverse of f(x)=(3\sqrt[3]{x}+1)/5 ?

The inverse of f(x)=(3\sqrt[3]{x}+1)/5 is (125x^3}{27}-\frac{25x^2)/9+(5x)/9-1/27

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inverse of f(x)=(3\sqrt[3]{x}+1)/5

inverse

\frac{125 x ^{3}}{27} - \frac{25 x ^{2}}{9} + \frac{5 x}{9} - \frac{1}{27}

Solution steps

Replace

x

with

y

Solve for

\frac{125 x ^{3}}{27} - \frac{25 x ^{2}}{9} + \frac{5 x}{9} - \frac{1}{27}

\frac{2}{3 x + 12}

f (x) = (x + 5)^{2}, x \leq - 5

f (x) = \frac{x ^{3} - 8}{x ^{2} + x - 6}

f (x) = \frac{4 x + 2}{x - 3}

\frac{x ^{2} + 4}{x}

What is the inverse of f(x)=(3\sqrt[3]{x}+1)/5 ?
The inverse of f(x)=(3\sqrt[3]{x}+1)/5 is (125x^3}{27}-\frac{25x^2)/9+(5x)/9-1/27