What is the inverse of f(x)=(x+5)^2,x<=-5 ?

The inverse of f(x)=(x+5)^2,x<=-5 is sqrt(x)-5,-sqrt(x)-5

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inverse of f(x)=(x+5)^2,x<=-5

inverse

f (x) = (x + 5)^{2}, x \leq - 5

x - 5, - x - 5

Solution steps

y = (x + 5)^{2}

Replace

x

with

y

x = (y + 5)^{2}

Solve for

y, x = (y + 5)^{2}

x - 5, - x - 5

f (x) = \frac{x ^{3} - 8}{x ^{2} + x - 6}

f (x) = \frac{4 x + 2}{x - 3}

\frac{x ^{2} + 4}{x}

x^{2} - 2 x - 4

x^{2} + 2

What is the inverse of f(x)=(x+5)^2,x<=-5 ?
The inverse of f(x)=(x+5)^2,x<=-5 is sqrt(x)-5,-sqrt(x)-5