What is the inverse of f(x)=2x^2+10x+1 ?

The inverse of f(x)=2x^2+10x+1 is (-5+sqrt(2x+23))/2 ,-(sqrt(2x+23)+5)/2

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inverse of f(x)=2x^2+10x+1

inverse

f (x) = 2 x^{2} + 10 x + 1

\frac{- 5 + 2 x + 23}{2}, - \frac{2 x + 23 + 5}{2}

Solution steps

y = 2 x^{2} + 10 x + 1

Replace

x

with

y

x = 2 y^{2} + 10 y + 1

Solve for

y, x = 2 y^{2} + 10 y + 1

\frac{- 5 + 2 x + 23}{2}, - \frac{2 x + 23 + 5}{2}

3 x - 2 y = 8

6 X - Y + 20 = 0

f (x) = \frac{2 x + 9}{3 x - 2}

f (x) = \frac{( x ^{2} + 1 )}{2 x ^{2} + 7}

(- 2, - 8), (- 6, - 2)

What is the inverse of f(x)=2x^2+10x+1 ?
The inverse of f(x)=2x^2+10x+1 is (-5+sqrt(2x+23))/2 ,-(sqrt(2x+23)+5)/2