What is the asymptotes of f(x)=((x^2+1))/(2x^2+7) ?

The asymptotes of f(x)=((x^2+1))/(2x^2+7) is Horizontal: y= 1/2

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asymptotes of f(x)=((x^2+1))/(2x^2+7)

asymptotes

f (x) = \frac{( x ^{2} + 1 )}{2 x ^{2} + 7}

Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{2 x ^{2} + 7} :

None

Horizontal Asymptotes of

\frac{x ^{2} + 1}{2 x ^{2} + 7} : y = \frac{1}{2}

Slant Asymptotes of

\frac{x ^{2} + 1}{2 x ^{2} + 7} :

None

Horizontal : y = \frac{1}{2}

(- 2, - 8), (- 6, - 2)

f (x) = \frac{5}{2} x - 3

f (x) = \frac{e ^{x}}{5 + e ^{x}}

y = \frac{3 x ^{2} - 3 x - 2}{x - 1}

x - 2 y = - 6

What is the asymptotes of f(x)=((x^2+1))/(2x^2+7) ?
The asymptotes of f(x)=((x^2+1))/(2x^2+7) is Horizontal: y= 1/2