What is the domain of f(x)= 1/(x^2+x-6) ?

The domain of f(x)= 1/(x^2+x-6) is x 2

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domain of f(x)= 1/(x^2+x-6)

domain

f (x) = \frac{1}{x ^{2} + x - 6}

x < - 3 or - 3 < x < 2 or x > 2

Interval Notation

(- \infty, - 3) \cup (- 3, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 3

The function domain

x < - 3 or - 3 < x < 2 or x > 2

y = - 5 x

f (x) = (- x^{2} + 16) (x + 1)

(1, - 4), (11, 8)

f (x) = lo g_{3} (x - 1)

f (x) = x^{2} (3 - x)^{2}

What is the domain of f(x)= 1/(x^2+x-6) ?
The domain of f(x)= 1/(x^2+x-6) is x<-3\lor-3<x<2\lor x>2