What is the domain of f(x)=sqrt((-x^2+16)(x+1)) ?

The domain of f(x)=sqrt((-x^2+16)(x+1)) is x<=-4\lor-1<= x<= 4

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domain of f(x)=sqrt((-x^2+16)(x+1))

domain

f (x) = (- x^{2} + 16) (x + 1)

x \leq - 4 or - 1 \leq x \leq 4

Solution steps

Find non-negative values for radicals:

x \leq - 4 or - 1 \leq x \leq 4

The function domain

x \leq - 4 or - 1 \leq x \leq 4

(1, - 4), (11, 8)

f (x) = lo g_{3} (x - 1)

f (x) = x^{2} (3 - x)^{2}

f (x) = x^{2} + 6 x + 8

y = 2 x^{2} - 16

What is the domain of f(x)=sqrt((-x^2+16)(x+1)) ?
The domain of f(x)=sqrt((-x^2+16)(x+1)) is x<=-4\lor-1<= x<= 4