What is the inverse of f(x)=-2x^2+4x-1 ?

The inverse of f(x)=-2x^2+4x-1 is -(-4+sqrt(-8x+8))/4 ,-(-4-sqrt(-8x+8))/4

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inverse of f(x)=-2x^2+4x-1

inverse

f (x) = - 2 x^{2} + 4 x - 1

- \frac{- 4 + - 8 x + 8}{4}, - \frac{- 4 - - 8 x + 8}{4}

Solution steps

y = - 2 x^{2} + 4 x - 1

Replace

x

with

y

x = - 2 y^{2} + 4 y - 1

Solve for

y, x = - 2 y^{2} + 4 y - 1

- \frac{- 4 + - 8 x + 8}{4}, - \frac{- 4 - - 8 x + 8}{4}

f (x) = \frac{1}{3} (x + 1)^{2} - 2

f (x) = \frac{x ^{2}}{16}

f (x) = x^{3} - 2 x^{2} - 15 x + 10

f (x) = x^{3} + 2 x^{2} + x - 7

x (n) = cos (3 n)

What is the inverse of f(x)=-2x^2+4x-1 ?
The inverse of f(x)=-2x^2+4x-1 is -(-4+sqrt(-8x+8))/4 ,-(-4-sqrt(-8x+8))/4