What is the inverse of f(x)=(x^2)/(16) ?

The inverse of f(x)=(x^2)/(16) is 4sqrt(x),-4sqrt(x)

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inverse of f(x)=(x^2)/(16)

inverse

f (x) = \frac{x ^{2}}{16}

4 x, - 4 x

Solution steps

y = \frac{x ^{2}}{16}

Replace

x

with

y

x = \frac{y ^{2}}{16}

Solve for

y, x = \frac{y ^{2}}{16}

4 x, - 4 x

f (x) = x^{3} - 2 x^{2} - 15 x + 10

f (x) = x^{3} + 2 x^{2} + x - 7

x (n) = cos (3 n)

f (x) = \frac{x ^{2} + 12}{x - 2}

y = - x + 4 + 6

What is the inverse of f(x)=(x^2)/(16) ?
The inverse of f(x)=(x^2)/(16) is 4sqrt(x),-4sqrt(x)