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Popular >

extreme f(x)=-4t^2+6t-1

Solution

extreme points

f (x) = - 4 t^{2} + 6 t - 1

Solution

Maximum (\frac{3}{4}, \frac{5}{4})

Solution steps

f^{'} (t) = - 8 t + 6

Find intervals:

Increasing

: - \infty < t < \frac{3}{4},

Decreasing

: \frac{3}{4} < t < \infty

Plug

t = \frac{3}{4}

into

- 4 t^{2} + 6 t - 1 : \frac{5}{4}

Maximum (\frac{3}{4}, \frac{5}{4})

Popular Examples

domain of 1/(sqrt(12-t))domain

\frac{1}{12 - t}

range of 1/4 tan(1/8 x)-2 range

\frac{1}{4} tan (\frac{1}{8} x) - 2

asymptotes of f(x)=(x-2)/((x+2)(x-2))asymptotes

f (x) = \frac{x - 2}{( x + 2 ) ( x - 2 )}

extreme f(x)=sqrt(x^2-8x+20)extreme points

f (x) = x^{2} - 8 x + 20

domain of f(x)=(4x^2-1)/(|2x+1|)domain

f (x) = \frac{4 x ^{2} - 1}{∣ 2 x + 1 ∣}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-4t^2+6t-1 ?
The extreme f(x)=-4t^2+6t-1 is Maximum(3/4 , 5/4)