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Popular >

extreme f(x)=sqrt(x^2-8x+20)

Solution

extreme points

f (x) = x^{2} - 8 x + 20

Solution

Minimum (4, 2)

Solution steps

f^{'} (x) = \frac{x - 4}{x ^{2} - 8 x + 20}

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 4

into

x^{2} - 8 x + 20 : 2

Minimum (4, 2)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=sqrt(x^2-8x+20) ?
The extreme f(x)=sqrt(x^2-8x+20) is Minimum(4,2)