What is the critical f(x)=(x+1)(x-4)^2 ?

The critical f(x)=(x+1)(x-4)^2 is x= 2/3 ,x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=(x+1)(x-4)^2

critical points

f (x) = (x + 1) (x - 4)^{2}

x = \frac{2}{3}, x = 4

Solution steps

(x + 1) (x - 4)^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{2}{3}, x = 4

Identify critical points not in

f (x)

domain

Domain of

(x + 1) (x - 4)^{2} : - \infty < x < \infty

All critical points are in domain

x = \frac{2}{3}, x = 4

m

f (x) = lo g_{b} (x)

\frac{1}{x - 6}

f (x) = x^{2} - 4 x - 12

y = - x^{2} + 16 x - 94

What is the critical f(x)=(x+1)(x-4)^2 ?
The critical f(x)=(x+1)(x-4)^2 is x= 2/3 ,x=4