en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Functions >

range of f(x)=x^2-4x-12

Solution

range

f (x) = x^{2} - 4 x - 12

Solution

f (x) \geq - 16

+1

Interval Notation

[- 16, \infty)

Solution steps

Vertex of

x^{2} - 4 x - 12 :

Minimum

(2, - 16)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (2, - 16)

f (x) \geq - 16

Graph

Popular Examples

symmetry y=-x^2+16x-94

domain of f(x)=sqrt(8x)

asymptotes of f(x)=(2x+3)/(x+2)

extreme f(x)=e^{1/x}*(x+2)

intercepts of f(x)=x^2-100sqrt(x)+6

Frequently Asked Questions (FAQ)

What is the range of f(x)=x^2-4x-12 ?
The range of f(x)=x^2-4x-12 is f(x)>=-16