What is the inflection 6/11 (x^2-9)^{2/3} ?

The inflection 6/11 (x^2-9)^{2/3} is (-3sqrt(3),(6*18^{2/3})/(11)),(3sqrt(3),(6*18^{2/3})/(11))

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inflection 6/11 (x^2-9)^{2/3}

inflection points

\frac{6}{11} (x^{2} - 9)^{\frac{2}{3}}

(- 33, \frac{6 \cdot 1 8 ^{\frac{2}{3}}}{11}), (33, \frac{6 \cdot 1 8 ^{\frac{2}{3}}}{11})

Solution steps

f^{''} (x) = \frac{8 ( x ^{2} - 27 )}{33 ( x ^{2} - 9 ) ^{\frac{4}{3}}}

Find intervals:

Concave Upward

: - \infty < x < - 33,

Concave Downward

: - 33 < x < - 3,

Concave Downward

: - 3 < x < 3,

Concave Downward

: 3 < x < 3 \cdot 3^{\frac{1}{2}},

Concave Upward

: 3 \cdot 3^{\frac{1}{2}} < x < \infty

Plug

x = - 33

into

\frac{6}{11} (x^{2} - 9)^{\frac{2}{3}} : \frac{6 \cdot 1 8 ^{\frac{2}{3}}}{11}

(- 33, \frac{6 \cdot 1 8 ^{\frac{2}{3}}}{11})

Plug

x = 33

into

\frac{6}{11} (x^{2} - 9)^{\frac{2}{3}} : \frac{6 \cdot 1 8 ^{\frac{2}{3}}}{11}

(33, \frac{6 \cdot 1 8 ^{\frac{2}{3}}}{11})

(- 33, \frac{6 \cdot 1 8 ^{\frac{2}{3}}}{11}), (33, \frac{6 \cdot 1 8 ^{\frac{2}{3}}}{11})

- \frac{1}{3} cos (3 x)

(x - 2)^{3} (x - 1)

f (x) = \frac{7 x - 4}{8}

5 x - 6 y = 4, (3, 5)

y = \frac{8}{9} cos (\frac{π x}{4})

What is the inflection 6/11 (x^2-9)^{2/3} ?
The inflection 6/11 (x^2-9)^{2/3} is (-3sqrt(3),(6*18^{2/3})/(11)),(3sqrt(3),(6*18^{2/3})/(11))