What is the range of-1/3 cos(3x) ?

The range of-1/3 cos(3x) is -1/3 <= f(x)<= 1/3

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range of-1/3 cos(3x)

range

- \frac{1}{3} cos (3 x)

- \frac{1}{3} \leq f (x) \leq \frac{1}{3}

Solution steps

The range of the basic

cos

function is

- 1 \leq cos (3 x) \leq 1

- 1 \leq cos (3 x) \leq 1

Multiply the edges of the range by:

- \frac{1}{3}

- \frac{1}{3} \leq - \frac{1}{3} cos (3 x) \leq \frac{1}{3}

Therefore the range is

- \frac{1}{3} \leq f (x) \leq \frac{1}{3}

(x - 2)^{3} (x - 1)

f (x) = \frac{7 x - 4}{8}

5 x - 6 y = 4, (3, 5)

y = \frac{8}{9} cos (\frac{π x}{4})

(1, 2), (3, 4)

What is the range of-1/3 cos(3x) ?
The range of-1/3 cos(3x) is -1/3 <= f(x)<= 1/3