What is the asymptotes of f(x)=(sqrt(4x^2+1))/(3x-5) ?

The asymptotes of f(x)=(sqrt(4x^2+1))/(3x-5) is Vertical: x= 5/3 ,Horizontal: y= 2/3 ,y=-2/3

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asymptotes of f(x)=(sqrt(4x^2+1))/(3x-5)

asymptotes

f (x) = \frac{4 x ^{2} + 1}{3 x - 5}

Vertical : x = \frac{5}{3}, Horizontal : y = \frac{2}{3}, y = - \frac{2}{3}

Solution steps

Vertical asymptotes of

\frac{4 x ^{2} + 1}{3 x - 5} : x = \frac{5}{3}

Horizontal Asymptotes of

\frac{4 x ^{2} + 1}{3 x - 5} : y = \frac{2}{3}, y = - \frac{2}{3}

Slant Asymptotes of

\frac{4 x ^{2} + 1}{3 x - 5} :

None

Vertical : x = \frac{5}{3}, Horizontal : y = \frac{2}{3}, y = - \frac{2}{3}

12 x^{3}

y = 0

f (x) = x^{2} + 3 x + 2

f (x) = \frac{x}{4 x ^{2}}

(x - 6)^{2}

What is the asymptotes of f(x)=(sqrt(4x^2+1))/(3x-5) ?
The asymptotes of f(x)=(sqrt(4x^2+1))/(3x-5) is Vertical: x= 5/3 ,Horizontal: y= 2/3 ,y=-2/3