What is the domain of f(x)=sqrt(x^2+3x+2) ?

The domain of f(x)=sqrt(x^2+3x+2) is x =-1

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domain of f(x)=sqrt(x^2+3x+2)

domain

f (x) = x^{2} + 3 x + 2

x \leq - 2 or x \geq - 1

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq - 1

The function domain

x \leq - 2 or x \geq - 1

f (x) = \frac{x}{4 x ^{2}}

(x - 6)^{2}

x^{3} + 3 x^{2} + 3 x + 2

y = \frac{x - 4}{16 - 4 x}

- 3 x = 6 - y

What is the domain of f(x)=sqrt(x^2+3x+2) ?
The domain of f(x)=sqrt(x^2+3x+2) is x<=-2\lor x>=-1