What is the perpendicular y=8x-sqrt(3)-(8pi)/3 ?

The perpendicular y=8x-sqrt(3)-(8pi)/3 is y=-1/8 x+b

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perpendicular y=8x-sqrt(3)-(8pi)/3

perpendicular

y = - \frac{1}{8} x + b

Solution steps

Find the slope of

y = 8 x - 3 - \frac{8 π}{3} : m = 8

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{8}

Line with slope m=

- \frac{1}{8} : y = - \frac{1}{8} x + b

y = - \frac{1}{8} x + b

What is the perpendicular y=8x-sqrt(3)-(8pi)/3 ?
The perpendicular y=8x-sqrt(3)-(8pi)/3 is y=-1/8 x+b