What is the critical 4x-x^3 ?

The critical 4x-x^3 is x=-2/(sqrt(3)),x= 2/(sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical 4x-x^3

critical points

4 x - x^{3}

x = - \frac{2}{3}, x = \frac{2}{3}

Solution steps

4 x - x^{3}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{2}{3}, x = \frac{2}{3}

Identify critical points not in

f (x)

domain

Domain of

4 x - x^{3} : - \infty < x < \infty

All critical points are in domain

x = - \frac{2}{3}, x = \frac{2}{3}

x^{3} + x - 9

f (x) = 7 x^{3}

y = 5 x + 13

f (x) = \frac{x - 1}{x - 2}

(5, 2), (- 3, - 4)

What is the critical 4x-x^3 ?
The critical 4x-x^3 is x=-2/(sqrt(3)),x= 2/(sqrt(3))