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midpoint
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amplitude of f(x)=5cos(4x)amplitude inverse of g(x)=2x-3inverse perpendicular y=8x-sqrt(3)-(8pi)/3perpendicular domain of 2x-10domain parity sec(3θcot(3θ))parity
Frequently Asked Questions (FAQ)
What is the midpoint (8,-9),(0,5) ?
The midpoint (8,-9),(0,5) is (4,-2)