What is the inverse of f(x)=((x-3))/(x+2) ?

The inverse of f(x)=((x-3))/(x+2) is (-3-2x)/(x-1)

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inverse of f(x)=((x-3))/(x+2)

inverse

f (x) = \frac{( x - 3 )}{x + 2}

\frac{- 3 - 2 x}{x - 1}

Solution steps

y = \frac{x - 3}{x + 2}

Replace

x

with

y

x = \frac{y - 3}{y + 2}

Solve for

y, x = \frac{y - 3}{y + 2}

\frac{- 3 - 2 x}{x - 1}

f (x) = x^{2} - 10 x + 25

4 x^{2} + 32 x + 61

f (x) = - 1.8 x + 9

y = \frac{1}{5} x - \frac{1}{8}, (0, 0)

3 x + 5 y = - 7

What is the inverse of f(x)=((x-3))/(x+2) ?
The inverse of f(x)=((x-3))/(x+2) is (-3-2x)/(x-1)