What is the perpendicular y= 1/5 x-1/8 ,(0,0) ?

The perpendicular y= 1/5 x-1/8 ,(0,0) is y=-5x

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perpendicular y= 1/5 x-1/8 ,(0,0)

perpendicular

y = \frac{1}{5} x - \frac{1}{8}, (0, 0)

y = - 5 x

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{1}{5} x - \frac{1}{8}

that passes through

(0, 0)

Find the slope of

y = \frac{1}{5} x - \frac{1}{8} : m = \frac{1}{5}

Compute the slope of the perpendicular line:

m_{p} = - 5

Find the line with slope m=

- 5

and passing through

(0, 0) : y = - 5 x

y = - 5 x

3 x + 5 y = - 7

x^{3} + 2 x^{2} - 8 x

f (x) = x^{3} + 1

tan (lo g_{8} (3 + 9^{x}))

f (x) = \frac{- x ^{2} - x + 12}{2 x + 8}

What is the perpendicular y= 1/5 x-1/8 ,(0,0) ?
The perpendicular y= 1/5 x-1/8 ,(0,0) is y=-5x