What is the inverse of f(x)=log_{3}(-x-4)-1 ?

The inverse of f(x)=log_{3}(-x-4)-1 is -3^{x+1}-4

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inverse of f(x)=log_{3}(-x-4)-1

inverse

f (x) = lo g_{3} (- x - 4) - 1

- 3^{x + 1} - 4

Solution steps

y = lo g_{3} (- x - 4) - 1

Replace

x

with

y

x = lo g_{3} (- y - 4) - 1

Solve for

y, x = lo g_{3} (- y - 4) - 1

- 3^{x + 1} - 4

f (x) = \frac{x ^{2}}{x ^{2} - 25}

y = \frac{- 3}{4} x + 2

\frac{2 + x}{x + 1}

f (x) = \frac{3}{x}

f (x) = \frac{6}{( x - 1 ) ^{3}}

What is the inverse of f(x)=log_{3}(-x-4)-1 ?
The inverse of f(x)=log_{3}(-x-4)-1 is -3^{x+1}-4