What is the critical f(x)=(x^2)/(x^2-25) ?

The critical f(x)=(x^2)/(x^2-25) is x=0

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critical f(x)=(x^2)/(x^2-25)

critical points

f (x) = \frac{x ^{2}}{x ^{2} - 25}

x = 0

Solution steps

\frac{x ^{2}}{x ^{2} - 25}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 5, x = 5

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{x ^{2} - 25} : x < - 5 or - 5 < x < 5 or x > 5

\frac{x ^{2}}{x ^{2} - 25}

is not defined at

x = - 5, x = 5

, therefore:

x = 0

y = \frac{- 3}{4} x + 2

\frac{2 + x}{x + 1}

f (x) = \frac{3}{x}

f (x) = \frac{6}{( x - 1 ) ^{3}}

1 + x - x^{2} - x^{3}

What is the critical f(x)=(x^2)/(x^2-25) ?
The critical f(x)=(x^2)/(x^2-25) is x=0