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Popular >

range of-x^2-5

Solution

range

- x^{2} - 5

Solution

f (x) \leq - 5

+1

Solution steps

Vertex of

- x^{2} - 5 :

Maximum

(0, - 5)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (0, - 5)

f (x) \leq - 5

Popular Examples

midpoint (10,5),(4,-1)midpoint

(10, 5), (4, - 1)

critical f(x)=1-5x critical points

f (x) = 1 - 5 x

domain of f(x)=(1-e^{x^2})/(1-e^{1-x^2)}domain

f (x) = \frac{1 - e ^{x^{2}}}{1 - e ^{1 - x^{2}}}

y = x^{2} - 6 x + 8

inverse of 10x-10 inverse

10 x - 10

Frequently Asked Questions (FAQ)

What is the range of-x^2-5 ?
The range of-x^2-5 is f(x)<=-5