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Popular >

midpoint (10,5),(4,-1)

Solution

midpoint

(10, 5), (4, - 1)

Solution

(7, 2)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (10, 5), (x_{2}, y_{2}) = (4, - 1)

= (\frac{4 + 10}{2}, \frac{- 1 + 5}{2})

Refine

= (7, 2)

Popular Examples

critical f(x)=1-5x critical points

f (x) = 1 - 5 x

domain of f(x)=(1-e^{x^2})/(1-e^{1-x^2)}domain

f (x) = \frac{1 - e ^{x^{2}}}{1 - e ^{1 - x^{2}}}

y = x^{2} - 6 x + 8

inverse of 10x-10 inverse

10 x - 10

parity f(x)=-4x^5+3x^2 parity

f (x) = - 4 x^{5} + 3 x^{2}

Frequently Asked Questions (FAQ)

What is the midpoint (10,5),(4,-1) ?
The midpoint (10,5),(4,-1) is (7,2)